3.1.93 \(\int \frac {(d+e x^2)^2 (a+b \text {csch}^{-1}(c x))}{x^8} \, dx\) [93]

Optimal. Leaf size=249 \[ -\frac {2 b c^3 \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right ) \sqrt {-1-c^2 x^2}}{11025 \sqrt {-c^2 x^2}}+\frac {b c d^2 \sqrt {-1-c^2 x^2}}{49 x^6 \sqrt {-c^2 x^2}}-\frac {2 b c d \left (15 c^2 d-49 e\right ) \sqrt {-1-c^2 x^2}}{1225 x^4 \sqrt {-c^2 x^2}}+\frac {b c \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right ) \sqrt {-1-c^2 x^2}}{11025 x^2 \sqrt {-c^2 x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3} \]

[Out]

-1/7*d^2*(a+b*arccsch(c*x))/x^7-2/5*d*e*(a+b*arccsch(c*x))/x^5-1/3*e^2*(a+b*arccsch(c*x))/x^3-2/11025*b*c^3*(3
60*c^4*d^2-1176*c^2*d*e+1225*e^2)*(-c^2*x^2-1)^(1/2)/(-c^2*x^2)^(1/2)+1/49*b*c*d^2*(-c^2*x^2-1)^(1/2)/x^6/(-c^
2*x^2)^(1/2)-2/1225*b*c*d*(15*c^2*d-49*e)*(-c^2*x^2-1)^(1/2)/x^4/(-c^2*x^2)^(1/2)+1/11025*b*c*(360*c^4*d^2-117
6*c^2*d*e+1225*e^2)*(-c^2*x^2-1)^(1/2)/x^2/(-c^2*x^2)^(1/2)

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Rubi [A]
time = 0.14, antiderivative size = 249, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {276, 6437, 12, 1279, 464, 277, 270} \begin {gather*} -\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}+\frac {b c d^2 \sqrt {-c^2 x^2-1}}{49 x^6 \sqrt {-c^2 x^2}}-\frac {2 b c d \sqrt {-c^2 x^2-1} \left (15 c^2 d-49 e\right )}{1225 x^4 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-c^2 x^2-1} \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right )}{11025 x^2 \sqrt {-c^2 x^2}}-\frac {2 b c^3 \sqrt {-c^2 x^2-1} \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right )}{11025 \sqrt {-c^2 x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((d + e*x^2)^2*(a + b*ArcCsch[c*x]))/x^8,x]

[Out]

(-2*b*c^3*(360*c^4*d^2 - 1176*c^2*d*e + 1225*e^2)*Sqrt[-1 - c^2*x^2])/(11025*Sqrt[-(c^2*x^2)]) + (b*c*d^2*Sqrt
[-1 - c^2*x^2])/(49*x^6*Sqrt[-(c^2*x^2)]) - (2*b*c*d*(15*c^2*d - 49*e)*Sqrt[-1 - c^2*x^2])/(1225*x^4*Sqrt[-(c^
2*x^2)]) + (b*c*(360*c^4*d^2 - 1176*c^2*d*e + 1225*e^2)*Sqrt[-1 - c^2*x^2])/(11025*x^2*Sqrt[-(c^2*x^2)]) - (d^
2*(a + b*ArcCsch[c*x]))/(7*x^7) - (2*d*e*(a + b*ArcCsch[c*x]))/(5*x^5) - (e^2*(a + b*ArcCsch[c*x]))/(3*x^3)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*
c*(m + 1))), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 276

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 277

Int[(x_)^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[x^(m + 1)*((a + b*x^n)^(p + 1)/(a*(m + 1))), x]
- Dist[b*((m + n*(p + 1) + 1)/(a*(m + 1))), Int[x^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, m, n, p}, x]
&& ILtQ[Simplify[(m + 1)/n + p + 1], 0] && NeQ[m, -1]

Rule 464

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[c*(e*x)^(m +
1)*((a + b*x^n)^(p + 1)/(a*e*(m + 1))), x] + Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(a*e^n*(m + 1)), In
t[(e*x)^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b*c - a*d, 0] && (IntegerQ[n] ||
GtQ[e, 0]) && ((GtQ[n, 0] && LtQ[m, -1]) || (LtQ[n, 0] && GtQ[m + n, -1])) &&  !ILtQ[p, -1]

Rule 1279

Int[((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Wit
h[{Qx = PolynomialQuotient[(a + b*x^2 + c*x^4)^p, f*x, x], R = PolynomialRemainder[(a + b*x^2 + c*x^4)^p, f*x,
x]}, Simp[R*(f*x)^(m + 1)*((d + e*x^2)^(q + 1)/(d*f*(m + 1))), x] + Dist[1/(d*f^2*(m + 1)), Int[(f*x)^(m + 2)
*(d + e*x^2)^q*ExpandToSum[d*f*(m + 1)*(Qx/x) - e*R*(m + 2*q + 3), x], x], x]] /; FreeQ[{a, b, c, d, e, f, q},
x] && NeQ[b^2 - 4*a*c, 0] && IGtQ[p, 0] && LtQ[m, -1]

Rule 6437

Int[((a_.) + ArcCsch[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_.)*((d_.) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u
= IntHide[(f*x)^m*(d + e*x^2)^p, x]}, Dist[a + b*ArcCsch[c*x], u, x] - Dist[b*c*(x/Sqrt[(-c^2)*x^2]), Int[Simp
lifyIntegrand[u/(x*Sqrt[-1 - c^2*x^2]), x], x], x]] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && ((IGtQ[p, 0] &&
!(ILtQ[(m - 1)/2, 0] && GtQ[m + 2*p + 3, 0])) || (IGtQ[(m + 1)/2, 0] &&  !(ILtQ[p, 0] && GtQ[m + 2*p + 3, 0]))
|| (ILtQ[(m + 2*p + 1)/2, 0] &&  !ILtQ[(m - 1)/2, 0]))

Rubi steps

\begin {align*} \int \frac {\left (d+e x^2\right )^2 \left (a+b \text {csch}^{-1}(c x)\right )}{x^8} \, dx &=-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}-\frac {(b c x) \int \frac {-15 d^2-42 d e x^2-35 e^2 x^4}{105 x^8 \sqrt {-1-c^2 x^2}} \, dx}{\sqrt {-c^2 x^2}}\\ &=-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}-\frac {(b c x) \int \frac {-15 d^2-42 d e x^2-35 e^2 x^4}{x^8 \sqrt {-1-c^2 x^2}} \, dx}{105 \sqrt {-c^2 x^2}}\\ &=\frac {b c d^2 \sqrt {-1-c^2 x^2}}{49 x^6 \sqrt {-c^2 x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}-\frac {(b c x) \int \frac {6 d \left (15 c^2 d-49 e\right )-245 e^2 x^2}{x^6 \sqrt {-1-c^2 x^2}} \, dx}{735 \sqrt {-c^2 x^2}}\\ &=\frac {b c d^2 \sqrt {-1-c^2 x^2}}{49 x^6 \sqrt {-c^2 x^2}}-\frac {2 b c d \left (15 c^2 d-49 e\right ) \sqrt {-1-c^2 x^2}}{1225 x^4 \sqrt {-c^2 x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}-\frac {\left (b c \left (-360 c^4 d^2+1176 c^2 d e-1225 e^2\right ) x\right ) \int \frac {1}{x^4 \sqrt {-1-c^2 x^2}} \, dx}{3675 \sqrt {-c^2 x^2}}\\ &=\frac {b c d^2 \sqrt {-1-c^2 x^2}}{49 x^6 \sqrt {-c^2 x^2}}-\frac {2 b c d \left (15 c^2 d-49 e\right ) \sqrt {-1-c^2 x^2}}{1225 x^4 \sqrt {-c^2 x^2}}+\frac {b c \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right ) \sqrt {-1-c^2 x^2}}{11025 x^2 \sqrt {-c^2 x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}+\frac {\left (2 b c^3 \left (-360 c^4 d^2+1176 c^2 d e-1225 e^2\right ) x\right ) \int \frac {1}{x^2 \sqrt {-1-c^2 x^2}} \, dx}{11025 \sqrt {-c^2 x^2}}\\ &=-\frac {2 b c^3 \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right ) \sqrt {-1-c^2 x^2}}{11025 \sqrt {-c^2 x^2}}+\frac {b c d^2 \sqrt {-1-c^2 x^2}}{49 x^6 \sqrt {-c^2 x^2}}-\frac {2 b c d \left (15 c^2 d-49 e\right ) \sqrt {-1-c^2 x^2}}{1225 x^4 \sqrt {-c^2 x^2}}+\frac {b c \left (360 c^4 d^2-1176 c^2 d e+1225 e^2\right ) \sqrt {-1-c^2 x^2}}{11025 x^2 \sqrt {-c^2 x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{7 x^7}-\frac {2 d e \left (a+b \text {csch}^{-1}(c x)\right )}{5 x^5}-\frac {e^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 x^3}\\ \end {align*}

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Mathematica [A]
time = 0.16, size = 152, normalized size = 0.61 \begin {gather*} \frac {-105 a \left (15 d^2+42 d e x^2+35 e^2 x^4\right )+b c \sqrt {1+\frac {1}{c^2 x^2}} x \left (1225 e^2 x^4 \left (1-2 c^2 x^2\right )+294 d e x^2 \left (3-4 c^2 x^2+8 c^4 x^4\right )-45 d^2 \left (-5+6 c^2 x^2-8 c^4 x^4+16 c^6 x^6\right )\right )-105 b \left (15 d^2+42 d e x^2+35 e^2 x^4\right ) \text {csch}^{-1}(c x)}{11025 x^7} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x^2)^2*(a + b*ArcCsch[c*x]))/x^8,x]

[Out]

(-105*a*(15*d^2 + 42*d*e*x^2 + 35*e^2*x^4) + b*c*Sqrt[1 + 1/(c^2*x^2)]*x*(1225*e^2*x^4*(1 - 2*c^2*x^2) + 294*d
*e*x^2*(3 - 4*c^2*x^2 + 8*c^4*x^4) - 45*d^2*(-5 + 6*c^2*x^2 - 8*c^4*x^4 + 16*c^6*x^6)) - 105*b*(15*d^2 + 42*d*
e*x^2 + 35*e^2*x^4)*ArcCsch[c*x])/(11025*x^7)

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Maple [A]
time = 0.34, size = 223, normalized size = 0.90

method	result	size
derivativedivides	\(c^{7} \left (\frac {a \left (-\frac {e^{2}}{3 c^{3} x^{3}}-\frac {2 d e}{5 c^{3} x^{5}}-\frac {d^{2}}{7 c^{3} x^{7}}\right )}{c^{4}}+\frac {b \left (-\frac {\mathrm {arccsch}\left (c x \right ) e^{2}}{3 c^{3} x^{3}}-\frac {2 \,\mathrm {arccsch}\left (c x \right ) d e}{5 c^{3} x^{5}}-\frac {\mathrm {arccsch}\left (c x \right ) d^{2}}{7 c^{3} x^{7}}-\frac {\left (c^{2} x^{2}+1\right ) \left (720 c^{10} d^{2} x^{6}-2352 c^{8} d e \,x^{6}-360 c^{8} d^{2} x^{4}+2450 c^{6} e^{2} x^{6}+1176 c^{6} d e \,x^{4}+270 c^{6} d^{2} x^{2}-1225 c^{4} e^{2} x^{4}-882 c^{4} d e \,x^{2}-225 c^{4} d^{2}\right )}{11025 \sqrt {\frac {c^{2} x^{2}+1}{c^{2} x^{2}}}\, c^{8} x^{8}}\right )}{c^{4}}\right )\)	\(223\)
default	\(c^{7} \left (\frac {a \left (-\frac {e^{2}}{3 c^{3} x^{3}}-\frac {2 d e}{5 c^{3} x^{5}}-\frac {d^{2}}{7 c^{3} x^{7}}\right )}{c^{4}}+\frac {b \left (-\frac {\mathrm {arccsch}\left (c x \right ) e^{2}}{3 c^{3} x^{3}}-\frac {2 \,\mathrm {arccsch}\left (c x \right ) d e}{5 c^{3} x^{5}}-\frac {\mathrm {arccsch}\left (c x \right ) d^{2}}{7 c^{3} x^{7}}-\frac {\left (c^{2} x^{2}+1\right ) \left (720 c^{10} d^{2} x^{6}-2352 c^{8} d e \,x^{6}-360 c^{8} d^{2} x^{4}+2450 c^{6} e^{2} x^{6}+1176 c^{6} d e \,x^{4}+270 c^{6} d^{2} x^{2}-1225 c^{4} e^{2} x^{4}-882 c^{4} d e \,x^{2}-225 c^{4} d^{2}\right )}{11025 \sqrt {\frac {c^{2} x^{2}+1}{c^{2} x^{2}}}\, c^{8} x^{8}}\right )}{c^{4}}\right )\)	\(223\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x^2+d)^2*(a+b*arccsch(c*x))/x^8,x,method=_RETURNVERBOSE)

[Out]

c^7*(a/c^4*(-1/3*e^2/c^3/x^3-2/5/c^3*d*e/x^5-1/7/c^3*d^2/x^7)+b/c^4*(-1/3*arccsch(c*x)*e^2/c^3/x^3-2/5*arccsch
(c*x)/c^3*d*e/x^5-1/7*arccsch(c*x)/c^3*d^2/x^7-1/11025*(c^2*x^2+1)*(720*c^10*d^2*x^6-2352*c^8*d*e*x^6-360*c^8*
d^2*x^4+2450*c^6*e^2*x^6+1176*c^6*d*e*x^4+270*c^6*d^2*x^2-1225*c^4*e^2*x^4-882*c^4*d*e*x^2-225*c^4*d^2)/((c^2*
x^2+1)/c^2/x^2)^(1/2)/c^8/x^8))

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Maxima [A]
time = 0.26, size = 232, normalized size = 0.93 \begin {gather*} \frac {1}{245} \, b d^{2} {\left (\frac {5 \, c^{8} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {7}{2}} - 21 \, c^{8} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {5}{2}} + 35 \, c^{8} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {3}{2}} - 35 \, c^{8} \sqrt {\frac {1}{c^{2} x^{2}} + 1}}{c} - \frac {35 \, \operatorname {arcsch}\left (c x\right )}{x^{7}}\right )} + \frac {2}{75} \, b d {\left (\frac {3 \, c^{6} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {5}{2}} - 10 \, c^{6} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {3}{2}} + 15 \, c^{6} \sqrt {\frac {1}{c^{2} x^{2}} + 1}}{c} - \frac {15 \, \operatorname {arcsch}\left (c x\right )}{x^{5}}\right )} e + \frac {1}{9} \, b {\left (\frac {c^{4} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {3}{2}} - 3 \, c^{4} \sqrt {\frac {1}{c^{2} x^{2}} + 1}}{c} - \frac {3 \, \operatorname {arcsch}\left (c x\right )}{x^{3}}\right )} e^{2} - \frac {a e^{2}}{3 \, x^{3}} - \frac {2 \, a d e}{5 \, x^{5}} - \frac {a d^{2}}{7 \, x^{7}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^2*(a+b*arccsch(c*x))/x^8,x, algorithm="maxima")

[Out]

1/245*b*d^2*((5*c^8*(1/(c^2*x^2) + 1)^(7/2) - 21*c^8*(1/(c^2*x^2) + 1)^(5/2) + 35*c^8*(1/(c^2*x^2) + 1)^(3/2)
- 35*c^8*sqrt(1/(c^2*x^2) + 1))/c - 35*arccsch(c*x)/x^7) + 2/75*b*d*((3*c^6*(1/(c^2*x^2) + 1)^(5/2) - 10*c^6*(
1/(c^2*x^2) + 1)^(3/2) + 15*c^6*sqrt(1/(c^2*x^2) + 1))/c - 15*arccsch(c*x)/x^5)*e + 1/9*b*((c^4*(1/(c^2*x^2) +
1)^(3/2) - 3*c^4*sqrt(1/(c^2*x^2) + 1))/c - 3*arccsch(c*x)/x^3)*e^2 - 1/3*a*e^2/x^3 - 2/5*a*d*e/x^5 - 1/7*a*d
^2/x^7

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Fricas [A]
time = 0.35, size = 347, normalized size = 1.39 \begin {gather*} -\frac {3675 \, a x^{4} \cosh \left (1\right )^{2} + 3675 \, a x^{4} \sinh \left (1\right )^{2} + 4410 \, a d x^{2} \cosh \left (1\right ) + 1575 \, a d^{2} + 105 \, {\left (35 \, b x^{4} \cosh \left (1\right )^{2} + 35 \, b x^{4} \sinh \left (1\right )^{2} + 42 \, b d x^{2} \cosh \left (1\right ) + 15 \, b d^{2} + 14 \, {\left (5 \, b x^{4} \cosh \left (1\right ) + 3 \, b d x^{2}\right )} \sinh \left (1\right )\right )} \log \left (\frac {c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} + 1}{c x}\right ) + 1470 \, {\left (5 \, a x^{4} \cosh \left (1\right ) + 3 \, a d x^{2}\right )} \sinh \left (1\right ) + {\left (720 \, b c^{7} d^{2} x^{7} - 360 \, b c^{5} d^{2} x^{5} + 270 \, b c^{3} d^{2} x^{3} - 225 \, b c d^{2} x + 1225 \, {\left (2 \, b c^{3} x^{7} - b c x^{5}\right )} \cosh \left (1\right )^{2} + 1225 \, {\left (2 \, b c^{3} x^{7} - b c x^{5}\right )} \sinh \left (1\right )^{2} - 294 \, {\left (8 \, b c^{5} d x^{7} - 4 \, b c^{3} d x^{5} + 3 \, b c d x^{3}\right )} \cosh \left (1\right ) - 98 \, {\left (24 \, b c^{5} d x^{7} - 12 \, b c^{3} d x^{5} + 9 \, b c d x^{3} - 25 \, {\left (2 \, b c^{3} x^{7} - b c x^{5}\right )} \cosh \left (1\right )\right )} \sinh \left (1\right )\right )} \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}}}{11025 \, x^{7}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^2*(a+b*arccsch(c*x))/x^8,x, algorithm="fricas")

[Out]

-1/11025*(3675*a*x^4*cosh(1)^2 + 3675*a*x^4*sinh(1)^2 + 4410*a*d*x^2*cosh(1) + 1575*a*d^2 + 105*(35*b*x^4*cosh
(1)^2 + 35*b*x^4*sinh(1)^2 + 42*b*d*x^2*cosh(1) + 15*b*d^2 + 14*(5*b*x^4*cosh(1) + 3*b*d*x^2)*sinh(1))*log((c*
x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) + 1)/(c*x)) + 1470*(5*a*x^4*cosh(1) + 3*a*d*x^2)*sinh(1) + (720*b*c^7*d^2*x^7
- 360*b*c^5*d^2*x^5 + 270*b*c^3*d^2*x^3 - 225*b*c*d^2*x + 1225*(2*b*c^3*x^7 - b*c*x^5)*cosh(1)^2 + 1225*(2*b*c
^3*x^7 - b*c*x^5)*sinh(1)^2 - 294*(8*b*c^5*d*x^7 - 4*b*c^3*d*x^5 + 3*b*c*d*x^3)*cosh(1) - 98*(24*b*c^5*d*x^7 -
12*b*c^3*d*x^5 + 9*b*c*d*x^3 - 25*(2*b*c^3*x^7 - b*c*x^5)*cosh(1))*sinh(1))*sqrt((c^2*x^2 + 1)/(c^2*x^2)))/x^
7

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b \operatorname {acsch}{\left (c x \right )}\right ) \left (d + e x^{2}\right )^{2}}{x^{8}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x**2+d)**2*(a+b*acsch(c*x))/x**8,x)

[Out]

Integral((a + b*acsch(c*x))*(d + e*x**2)**2/x**8, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^2*(a+b*arccsch(c*x))/x^8,x, algorithm="giac")

[Out]

integrate((e*x^2 + d)^2*(b*arccsch(c*x) + a)/x^8, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (e\,x^2+d\right )}^2\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right )}{x^8} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((d + e*x^2)^2*(a + b*asinh(1/(c*x))))/x^8,x)

[Out]

int(((d + e*x^2)^2*(a + b*asinh(1/(c*x))))/x^8, x)

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